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6n^2+21n-12=0
a = 6; b = 21; c = -12;
Δ = b2-4ac
Δ = 212-4·6·(-12)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-27}{2*6}=\frac{-48}{12} =-4 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+27}{2*6}=\frac{6}{12} =1/2 $
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